diketahui f(x) = mx² + 2x - 1 dan f'(1) = -1. tentukan nilai dari m dan f(1)
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Jawaban:
m= -3/2
f(1)= -1/2
Penjelasan dengan langkah-langkah:
f'(x)= 2mx+2
f'(1)= -1
2m(1)+2= -1
2m= -3
m= -3/2
m= -3/2
Maka f(x)= -3/2x²+2x-1
f(1)= -3/2(1)²+2(1)-1
= -3/2+2-1
= 1/2-1
= -1/2
Jawab:
Penjelasan dengan langkah-langkah:
f(x) = mx² + 2x - 1
f'(1) = -1
f'(x) = 2mx + 2
f'(1) = 2m (1) + 2
-1 = 2m + 2
2m = -1 - 2
2m = -3
m = -3/2
f(x) = (-3/2)x² + 2x - 1
f(1) = (-3/2)(1)² + 2(1) - 1
f(1) = (-3/2) + 2 - 1
f(1) = (-3/2) + 1
f(1) = -1/2
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